silverdiesel Messages 64 Reaction score 0 Thread starter Feb 4, 2006 #1 These trig subs are killing me. [tex]\int\cos^5(x)dx[/tex]hints?
George Jones Staff Emeritus Science Advisor Gold Member Messages 7,643 Reaction score 1,602 Feb 4, 2006 #2 [tex]\cos^{5} x = \left(1 - \sin^2 x \right)^{2} \cos x[/tex] Regards, George
silverdiesel Messages 64 Reaction score 0 Feb 4, 2006 #3 Thanks George... I am slowly getting the hang of this. I appreciate your help.
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Feb 4, 2006 #4 One of the first things you should have learned: if you have sine or cosine to an odd power, factor out one of them to use with the dx. cos5 x dx= (cos4 x)(cos x dx) = (cos2 x)2 (cos x dx)= (1- sin2 x)2(cos x dx) Now, let u= sin x.
One of the first things you should have learned: if you have sine or cosine to an odd power, factor out one of them to use with the dx. cos5 x dx= (cos4 x)(cos x dx) = (cos2 x)2 (cos x dx)= (1- sin2 x)2(cos x dx) Now, let u= sin x.