MHB Match Parametric Equations with Graphs - Explanation Help for 21, 23, and 25

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match the parametric equations with the graphs. i need help with 21 23 and 25. i have the answers but i need explanations for why that specific graph matches with the set of equations. I've been stuck on these for a long time. please help!

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Let's look at the first one, 21.) What will its "shadow" in the $xz$ plane look like?
 
i don't know. i don't understand the question.
 
ineedhelpnow said:
i don't know. i don't understand the question.

Okay, ignore $y$ for the moment, what would the curve then defined by the parametric equations for $x$ and $z$ look like in the $xz$ plane?
 

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No, what if you had:

$$\begin{cases}x=\cos(t) \\[3pt] z=\sin(t) \\ \end{cases}$$

And then how would the factor of $t$ affect this?
 
im getting confused. x=cos t and z=sin t would make a circle.
 
ineedhelpnow said:
im getting confused. x=cos t and z=sin t would make a circle.

Yes, good! :D

So, then what do you think the $t$ in front of the trig functions would do to the circle?
 
i don't know. it affects the amplitude?
 
  • #10
ineedhelpnow said:
i don't know. it affects the amplitude?

Yes, that's one way to look at it, I think of it affecting the radius, it is in effect a circle with an increasing radius, which begins at zero, and increases linearly. So, what would we call a circle whose radius is increasing?
 
  • #11
a circle with an increasing radius :confused:
 
  • #12
ineedhelpnow said:
a circle with an increasing radius :confused:

Think of attempting to draw a circle, but the radius keeps growing as you wind around the center...what will you draw instead?
 
  • #13
thanks. i think i figured them out though
 
  • #14
ineedhelpnow said:
thanks. i think i figured them out though

Well, alrighty then. (Smoking)
 
  • #15
i got the first and second but I am still stuck on the last one (25)
 
  • #16
It is similar to the first one. If you ignore $z$, what would you have in the $xy$-plane?
 
  • #18
the z was meant to be an x but its still a circle
 
  • #19
ineedhelpnow said:
its a circle. i wanted to upload a pic but the uploader is being dumb graph z'=' cos 8t and y'=' sin 8t - Wolfram|Alpha

Yes, it's indeed a circle with a fixed radius of one unit, so we know we will have a helical curve of some sort. What does the equation for $z$ tell us about how the helix will climb?
 
  • #20
as t increases so does z so I am guessing a circle on the xy plane that increases across z so IV
 
  • #21
Yes, since $z$ increases exponentially, we then expect the helix to climb exponentially. So IV does seem to fit the bill. :D
 
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