Math Problem: Find # of Elements in 2nd/3rd Subsets

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Discussion Overview

The discussion revolves around a mathematical problem involving a set of 200 elements partitioned into three subsets, with a focus on determining the number of elements in the second and third subsets. Participants explore the relationships between the subsets based on given conditions, including equations relating their cardinalities.

Discussion Character

  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant presents the problem and their initial approach, expressing confusion about the relationship between the subsets and the final answer.
  • Another participant proposes a method using variables for the cardinalities of the subsets, leading to the equations A + 2B = 200 and 4B = 3A, ultimately finding B = 60.
  • Some participants clarify that the answer of 120 refers to the total number of elements in the union of the second and third subsets, not the count of elements in either subset individually.
  • There is a reiteration of the clarification regarding the interpretation of the question, emphasizing that the total count includes elements in both subsets.

Areas of Agreement / Disagreement

Participants generally agree on the mathematical approach to solving the problem, but there is some confusion regarding the interpretation of the question about whether it asks for the count of elements in one subset or the total in both.

Contextual Notes

Some participants express uncertainty about the interpretation of the question, specifically whether it is asking for the number of elements in one subset or the combined total of the second and third subsets.

elimeli
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I am practicing for my math exam next week and I came across this problem:

A set has 200 elements in it. It is partitioned into three subsets so that the second and third subsets have the same number of elements. If four times the number of elements in the second subset is three times as many as in the first, how many elements are in either the second or third subset?

The answer is 120, but I don't understand how to get to that answer.

I equaled 4 nx(2) = 3 nx(1), and so I got that 4nx(2)/3 = nx(1). I then plugged that into 200 = nx(2) + nx(2) + 4nx(2)/3 and got that nx(2)=60. The answer is 120, so I would have to multiply my answer by 2 to get it and I do not understand why, since the answer is asking for either the second or third subset and not the addition of the two.

Can anybody explain?
 
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I would let $A$ be the cardinality of the first subset, and $B$ be the cardinality of the second and third subsets, so that we have:

$$A+2B=200$$

$$4B=3A\implies A=\frac{4}{3}B$$

Substituting for $A$ into the first equation we get:

$$\frac{4}{3}B+2B=200$$

Multiply through by $$\frac{3}{2}$$:

$$2B+3B=300$$

$$5B=300$$

$$B=60$$

Thus, the cardinality of the union of the second and third subsets is:

$$2B=120$$
 
MarkFL said:
I would let $A$ be the cardinality of the first subset, and $B$ be the cardinality of the second and third subsets, so that we have:

$$A+2B=200$$

$$4B=3A\implies A=\frac{4}{3}B$$

Substituting for $A$ into the first equation we get:

$$\frac{4}{3}B+2B=200$$

Multiply through by $$\frac{3}{2}$$:

$$2B+3B=300$$

$$5B=300$$

$$B=60$$

Thus, the cardinality of the union of the second and third subsets is:

$$2B=120$$

But why is the answer the union of the second and third subsets if the question is asking for either one of them? Shouldn't it be 60? Or am I misinterpreting the question?
 
The question asks how many elements are in either the second or third subsets, so they are asking for the total number of elements in the union of the two subsets. If an element is in either the second or third subset, then it is to be counted. :)
 
MarkFL said:
The question asks how many elements are in either the second or third subsets, so they are asking for the total number of elements in the union of the two subsets. If an element is in either the second or third subset, then it is to be counted. :)

I see. Thank you so much for clarifying!
 

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