1. The problem statement, all variables and given/known data sqrt(2x+4) = sqrt(6x+1) - 1 I Need to solve for x, but cannot seem to get the same answer as the text. (Ans. x= 5/2) 3. The attempt at a solution sqrt(2x+4) - sqrt(6x+1) = -1 square both sides (2x+4) - (6x+1) = 1 -4x-3=1 -4x=4 x=-1 ?? I know I must be doing something wrong, it has been a while since I have done this sort of problem. Thank you for your time.
Your mistake is in thinking (a-b)^{2} = a^{2}-b^{2}, which is what you did when you squared the lefthand side of the equation. You need to multiply it out correctly.
Im still not there yet: My new attempt: I cant seem to get rid of the sqrt (x) i know sqrt(12x) = 2*sqrt(3x)
Now you're making even more mistakes. First, [sqrt(2x+4)-sqrt(6x+1)]^{2} ≠ (2x+4) - (6x+1) Second, sqrt(a+b) ≠ sqrt(a)+sqrt(b) which is what you're doing going from the fifth line to the sixth line. You were, however, correct when you said earlier that (sqrt(2x+4))^{2} = 2x+4 The problem is actually a bit easier to solve if you square both sides right away: (sqrt(2x+4))^{2} = (sqrt(6x+1)-1)^{2} To correctly calculate the righthand side, let a=sqrt(6x+1) and b=1. Then your equation becomes (sqrt(2x+4))^{2} = (a-b)^{2} Now FOIL out the righthand side and then substitute back in for a and b.
Im sorry, I am unable to see that. All i can see is black and faint white portions. Is it possible for you to take a screen shot and upload to image shack?
I got it, thank you for your help. It took a while to come back to me. I appreciate your time, thank you.