The mathematical function discussed is defined as \( f(x) = \frac{2}{\sqrt{x}} \). When evaluating this function at \( x = \frac{1}{25} \), the calculation proceeds as follows: \( \sqrt{\frac{1}{25}} = \frac{1}{5} \), leading to \( f\left(\frac{1}{25}\right) = \frac{2}{\frac{1}{5}} = 2 \cdot 5 = 10 \). Thus, \( f\left(\frac{1}{25}\right) \) equals 10, clarifying that \( \frac{1}{25} \) does not directly become 10, but rather, it is the output of the function.
PREREQUISITESStudents learning algebra, educators teaching mathematical functions, and anyone interested in understanding function evaluations and transformations.
the said:
