Mathematica to recognize e−iθ as the eulers identity

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SUMMARY

Mathematica can recognize Euler's identity, e^{-iθ} = cos(θ) + i*sin(θ), through the use of the Exp function. To visualize this identity, users can utilize the Plot function with the imaginary part of the exponential function. A specific example provided is: Plot[Im@Exp[-I x], {x, -5, 5}, PlotStyle -> Thick, ColorFunction -> "StarryNightColors"]. This approach effectively displays the sine component of the identity on a graph.

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arierreF
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I just need to know how can Mathematica recognize e^{-i\theta} as the eulers identity. This is, e^{-i\theta} = cos \theta + sin \theta.


When i plot a function like e^{i\theta}, nothings appear in the graph.

Help is appreciated.
 
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You can use something fancy like this:
Code:
Plot[Im@Exp[-I x], {x, -5, 5}, PlotStyle -> Thick, 
 ColorFunction -> "StarryNightColors"]
Nh4ihZW.png
 
Thanks it works!
 

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