Maths problem(mechanics-friction)

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SUMMARY

The discussion focuses on calculating the coefficient of friction for a particle sliding down a rough plane inclined at 30° to the horizontal. The particle travels a distance of 2.25 m in 1.5 seconds. The correct coefficient of friction, as per the reference book, is 0.346. The initial approach using the equations for friction was incorrect, as the user misapplied the force of gravity instead of formulating an overall force equation. Key insights include the importance of using SUVAT equations and drawing a diagram to visualize forces.

PREREQUISITES
  • Understanding of mechanics, specifically inclined planes and friction.
  • Familiarity with SUVAT equations of motion.
  • Knowledge of basic trigonometry, particularly sine and cosine functions.
  • Ability to draw and interpret free-body diagrams.
NEXT STEPS
  • Study the derivation and application of the SUVAT equations in mechanics.
  • Learn how to construct and analyze free-body diagrams for inclined planes.
  • Explore the relationship between friction, normal force, and gravitational force in mechanics.
  • Practice solving similar problems involving motion on inclined planes with friction.
USEFUL FOR

This discussion is beneficial for students studying mechanics, physics educators, and anyone seeking to improve their problem-solving skills in dynamics involving friction on inclined planes.

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Maths problem(mechanics--friction)

A and B are points on the same line of greatest slope of a rough plane inclined at 30◦ to the horizontal.
A is higher up the plane than B and the distance AB is 2.25 m. A particle P, of mass mkg, is released
from rest at A and reaches B 1.5 s later. Find the coefficient of friction between P and the plane.

According to the book the answer is 0.346 and i cannot get the answer:

according to me: friction = mg sin 30

Reaction= mg c0s 30

using F = μ R

i replace but yet cannot get the right answer...please try to work it out i think my method is wrong..?
 
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jinx007 said:
A and B are points on the same line of greatest slope of a rough plane inclined at 30◦ to the horizontal.
A is higher up the plane than B and the distance AB is 2.25 m. A particle P, of mass mkg, is released
from rest at A and reaches B 1.5 s later. Find the coefficient of friction between P and the plane.

According to the book the answer is 0.346 and i cannot get the answer:

according to me: friction = mg sin 30

Reaction= mg c0s 30

using F = μ R

i replace but yet cannot get the right answer...please try to work it out i think my method is wrong..?


Your equation for friction is totally wrong, what you have there is the equation of the force of gravity on the particle acting down the plane. However your two next equations are correct. Try to make an overall force equation. I'd really recommend drawing a diagram and labelling the forces.

Other things you'll have to consider;

Equations of motion, (SUVAT), you have the distance between A & B, and the time second to pass from one to the other. What can you work out from those 2 pieces of information that would be helpful here? (we're considering forces...). Also bear in mind it starts from rest so u = 0.
 

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