Matrix Exponential: Solve Homework Equation w/ Initial Condition

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SUMMARY

The discussion centers on solving the differential equation x' = Ax, where A is the matrix [[0, 1], [-1, 0]]. The matrix exponential e^(At) is computed as [[cos(t), sin(t)], [-sin(t), cos(t)]]. The solution to the initial condition x(0) = [[1], [2]] is derived using the formula x(t) = e^(At)x(0), confirming that this approach satisfies both the ordinary differential equation (ODE) and the initial condition.

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Homework Statement



Given x' = Ax where A =

( 0 1 )
( -1 0 )

Compute the matrix exponential and then find the solution such that x(0) =

( 1 )
( 2 )

Homework Equations



The Attempt at a Solution



I computed the matrix exponential and obtained the matrix,

e^(A) =

( cos(t) sin(t) )
( -sin(t) cos(t) )

But I don't understand how to compute the initial condition. Am I supposed to compute the initial by multiplying the original A by x(0) and then compute the matrix exponential for the new A? Or multiple e^(A) by x(0)? My notes aren't very clear. But those are my only guesses..

Thanks for any help.
 
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What you computed was e^(At). And sure, your solution is then x(t)=e^(At)x(0). If you take d/dt of that then you get x'(t)=Ax(t), right?
 
Alright, I think I've got it. Compute x(t) then differentiate it?
 
You don't have to differentiate it, I was just pointing out why x(t)=e^(At)x(0) works as a solution. x'(t)=Ax(t) and x(0)=e^(0)x(0). It satisfies the ode and has the right initial condition.
 
Alright, thank you.
 

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