I Matrix form of metric component transformation?

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The discussion centers on the transformation of the metric tensor from unprimed to primed coordinates in general relativity. The transformation is presented in two forms: one from Moore's GR workbook and another from Schutz's GR textbook. The confusion arises regarding the equivalence of the two matrix forms, particularly how the indices are matched and interpreted. It is noted that different texts may define the indices of the partial derivatives differently, leading to potential misunderstandings. Clarifying these definitions is crucial for reconciling the two approaches to metric transformation.
farfromdaijoubu
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Question about the matrix form of a metric transformation from coordinate system to another.
The transformation of the metric from unprimed to primed coordinates is given in Moore's GR workbook as:
##g'_{uv} = \frac{\partial x^a}{\partial x^{'u}}

\frac{\partial x^b}{\partial x^{'v}}g_{ab}##

In matrix form, by matching indices on both sides (so that u and v are the outer 'indices'), I got
##(g'_{uv}) = \left(\frac{\partial x^a}{\partial x^{'u}}\right)^T (g_{ab})


\left( \frac{\partial x^b}{\partial x^{'v}} \right)##


But on pg. 146 of Schutz's GR textbook, he writes the matrix form of the transformation as $$(g') = $(\Lambda) (g) \Lambda)^T$$, where ##\Lambda = \left(\frac{\partial x^a}{\partial x^{u'}} \right)##.

How did he get this result? Did I misunderstand something? Because I don't think it's equivalent to what I got...

Thanks
 
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Different books may have different definitions of which of the indices of ##\partial x^a/\partial x^{u’}## is to be interpreted as the row index.
 
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