Matrix form of metric component transformation?

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SUMMARY

The transformation of the metric from unprimed to primed coordinates in General Relativity is represented in matrix form as \( g'_{uv} = \left(\frac{\partial x^a}{\partial x^{u'}}\right)^T (g_{ab}) \left(\frac{\partial x^b}{\partial x^{v'}}\right) \). This contrasts with Schutz's formulation on page 146, which presents the transformation as \( (g') = (\Lambda) (g) \Lambda^T \), where \( \Lambda = \left(\frac{\partial x^a}{\partial x^{u'}}\right) \). The discrepancy arises from differing interpretations of index placement in the transformation matrices, highlighting the importance of consistent notation in tensor calculus.

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farfromdaijoubu
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Question about the matrix form of a metric transformation from coordinate system to another.
The transformation of the metric from unprimed to primed coordinates is given in Moore's GR workbook as:
##g'_{uv} = \frac{\partial x^a}{\partial x^{'u}}

\frac{\partial x^b}{\partial x^{'v}}g_{ab}##

In matrix form, by matching indices on both sides (so that u and v are the outer 'indices'), I got
##(g'_{uv}) = \left(\frac{\partial x^a}{\partial x^{'u}}\right)^T (g_{ab})


\left( \frac{\partial x^b}{\partial x^{'v}} \right)##


But on pg. 146 of Schutz's GR textbook, he writes the matrix form of the transformation as $$(g') = $(\Lambda) (g) \Lambda)^T$$, where ##\Lambda = \left(\frac{\partial x^a}{\partial x^{u'}} \right)##.

How did he get this result? Did I misunderstand something? Because I don't think it's equivalent to what I got...

Thanks
 
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Different books may have different definitions of which of the indices of ##\partial x^a/\partial x^{u’}## is to be interpreted as the row index.
 
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