Matrix HELP! - Finding Matrices for AM = -MA

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The discussion focuses on finding 2x2 matrices A that satisfy the equation AM = -MA, where M is defined as the matrix M = [7 -3; 15 -7]. The matrix A is structured as A = [a b; b d], with the condition that the (1, 2) and (2, 1) entries are equal (b). The solution involves setting up a system of equations derived from matrix multiplication, leading to four key equations that must be solved to find the values of a, b, and d.

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theacerf1
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Matrix HELP!

Ok this question is in a cd quiz from a textbook, i have no idea what the question even means or how to do it. Please help!

Let M =

 7 −3
15 −7 .

Find all 2 × 2 matrices

A =
[ a b
b d ]

such that AM = −MA.
(Note that the solutions wanted should have equal (1, 2)- and (2, 1)-entries b.)
 
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M =
[7 -3
15 -7]

a 2x2 matrix
 


Did you even try? It is really just a matter of computation.

[tex]\begin{bmatrix}a & b \\ b & d\end{bmatrix}\begin{bmatrix}7 & -3 \\ 15 & -7\end{bmatrix}[/tex]
[tex]= \begin{bmatrix}7a+ 15b & -3a- 7b \\ 7b+ 15d & -3b- 7d\end{bmatrix}[/tex]
[tex]= -\begin{bmatrix}7 & -3 \\ 15 & -7\end{bmatrix}\begin{bmatrix}a & b \\ b & d\end{bmatrix}[/tex]
[tex]= \begin{bmatrix}-7a+ 3b & -7b+ 3d \\ -15a+ 7b & -15b+ 7d\end{bmatrix}[/tex]

So you must have 7a+ 15b= -7a+ 3b, -3a- 7b= -7b+ 3d, 7b+ 15d= -15a+ 7d, and -3b- 7d= -15b+ 7d.
 
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