Matrix Index Inversion: Clarification Needed

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    Inverse Matrix
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Discussion Overview

The discussion revolves around the clarification of matrix index inversion, specifically the relationship between the components of a metric tensor and its inverse. Participants explore the notation and implications of raising and lowering indices in the context of tensor mathematics.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions whether \(\frac{1}{g_{ab}}=g^{ba}\) is true, expressing confusion over index notation and inversion.
  • Another participant asserts that the statement is false, explaining that it would imply a matrix with reciprocal entries, which does not represent the inverse of a matrix.
  • A different participant clarifies that \(g^{ab}\) refers to the entry in row \(a\) and column \(b\) of the inverse of the matrix defined by \(g_{ab}\), emphasizing that the relationship does not hold for all matrix entries.
  • It is noted that if \(g^{ij}\) is the fundamental metric tensor, then \(g_{ij}=(g^{ij})^{-1}\) is true, but this does not equate to \(\frac{1}{g_{ij}}\).

Areas of Agreement / Disagreement

Participants express disagreement regarding the initial claim about index inversion, with multiple perspectives on the correct interpretation of the relationships between the components of the metric tensor and its inverse.

Contextual Notes

The discussion highlights the complexity of index notation and the conditions under which certain relationships hold, particularly in the context of matrix inversion and tensor components.

gentsagree
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is it true that [itex]\frac{1}{g_{ab}}=g^{ba}[/itex]? I am a bit confused by the index notation. I especially wonder about the inversion of the indices. Could somebody clarify this please?
 
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No, that's not true. That would be the matrix with reciprocal entries, which is obviously not the inverse.

It would take me a while to explain the index notation and lowering and raising indices (and some Latex work), which I am not feeling up to right now.
 
##g^{ab}## is the number on row a, column b of the inverse of the matrix that has ##g_{ab}## on row a, column b.

It's not true in general that if A is an invertible matrix, then ##(A^{-1})_{ij}=1/A_{ji}##. Even when A is diagonal, it's only true for the numbers on the diagonal.
 
IF [itex]g^{ij}[/itex] is intended as the fundamental metric tensor, [itex]ds^2= g^{ij}dx_idx_j[/itex], then it is true that [itex]g_{ij}= (g^{ij})^{-1}[/itex] but, again, that is NOT the same as [itex]\frac{1}{g_{ij}}[/itex].
 

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