Matrix representation of T with Basis B?

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SUMMARY

The discussion revolves around finding the matrix representation of the linear transformation T: P2 → P2 defined by T(a0 + a1t + a2t^2) = 3a0 + (5a0 - 2a1)t + (4a1 + a2)t^2 with respect to the basis B = {1, t, t^2}. The user clarifies that to compute T(1), T(t), and T(t^2), one must apply the transformation to each basis element. The resulting matrix representation is confirmed as [T]_B^B = [[3, 0, 0], [5, -2, 0], [0, 4, 1]].

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Fernando Revilla
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I quote un unsolved question posted in MHF on December 8th, 2012 by user bonfire09.

Problem is assuming the mapping T: P2---->P2 defined by T(a0+a1t+a2t2)=3a0+(5a0-2a1)t+(4a1+a2)t^2 is linear. Find the matrix representation of T relative to Basis B={1,t,t^2}.
The part that I am confused on is when I go plug in the basis values T(1),T(t),and T(t^2)? I don't know how to do it?

From my understanding T(a0+a1t+a2t2) can be written as a0T(1)+a1T(t)+a2T(t^2)
So to find T(1) its just a0T(1)+0T(t)+0T(t^2)=3a0+5a0t? Am i right?
 
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Really this is not a problem relative to change of basis. Take into account that according to a well-known theorem, to find the matrix of a linear map f:V\to W with respect to basis B_V,B_W of V,W respectively, you only need to find the coordinates of the image of the elements of B_V with respect to B_W and then, to write these as columns.

In our case T is an endomorphism and only one basis is mentioned, so B_V=B_W=B. We have:
$$T(1)=3+5t\\T(t)=-2t+4t^2\\T(t^2)=t^2$$
Hence, the corresponding matrix representation is:
$$[T]_B^B=\begin{bmatrix}{3}&{\;\;0}&{0}\\{5}&{-2}&{0}\\{0}&{\;\;4}&{1}\end{bmatrix}$$
 

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