Linear Mapping T: P2 to P2 with Basis B | Homework Help & Solution Explained"

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SUMMARY

The discussion focuses on the linear mapping T: P2 to P2 defined by T(a0 + a1t + a2t^2) = 3a0 + (5a0 - 2a1)t + (4a1 + a2)t^2. Participants clarify how to compute the matrix representation of T relative to the basis B = {1, t, t^2}. The correct evaluations are T(1) = 3 + 5t, T(t) = -2t + 4t^2, and T(t^2) = t^2, achieved by substituting appropriate coefficients a0, a1, and a2 for each basis element.

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  • Familiarity with polynomial spaces, specifically P2
  • Knowledge of matrix representation of linear transformations
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bonfire09
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Homework Statement


Problem is assuming the mapping T: P2---->P2 defined by T(a0+a1t+a2t2)=3a0+(5a0-2a1)t+(4a1+a2)t^2 is linear. Find the matrix representation of T relative to Basis B={1,t,t^2}.
The part that I am confused on is when I go plug in the basis values T(1),T(t),and T(t^2)? I don't know how to do it?

Homework Equations


The Attempt at a Solution

So to find T(1) its just T(1+0t+0t2)=3a0+5a0t

To find T(t) is just T(0+a1(t)+0T2)=3(0)+(5(0)-2a1)t+(4a1+0)t^2=-2a1t+4a1t^2

T(t^2)= T(0+0t+a2t^2)=3(0)+(5(0)-2(0))t+(4(0)+a2)t^2=a2T2

Usually in lots of books they omit steps like these and I'm trying to figure them out. Is this a correct way?
 
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bonfire09 said:

The Attempt at a Solution



So to find T(1) its just T(1+0t+0t2)=3a0+5a0t

To find T(t) is just T(0+a1(t)+0T2)=3(0)+(5(0)-2a1)t+(4a1+0)t^2=-2a1t+4a1t^2

T(t^2)= T(0+0t+a2t^2)=3(0)+(5(0)-2(0))t+(4(0)+a2)t^2=a2T2

Usually in lots of books they omit steps like these and I'm trying to figure them out. Is this a correct way?

This is the right idea, but to get [itex]T(1)[/itex] you take [itex]a_0 = 1[/itex], [itex]a_1 = 0[/itex], and [itex]a_2 = 0[/itex] so that [itex]T(1) = 3 + 5t[/itex]. Similarly for the other two basis vectors.
 
Oh ok. So for T(t) just let a0=0, a1=1 and a2=0 and for T(t^2) just let a0=0,a1=0 and a2=1?

That looks like the standard basis {e1,e2,e3}
 

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