Matrix Transformations around z axis

Click For Summary
SUMMARY

The matrix A that transforms space by rotating counterclockwise around the z-axis by π/4 is defined as follows: [ sqrt(2)/2 -sqrt(2)/2 0; sqrt(2)/2 sqrt(2)/2 0; 0 0 1]. The corresponding unit vector u that satisfies Au = u is (0, 0, 1), which is the eigenvector associated with the eigenvalue λ = 1. The only real eigenvalue of the matrix A is {1}, as the other computed eigenvalues are complex.

PREREQUISITES
  • Understanding of matrix transformations and rotations in 3D space.
  • Knowledge of eigenvalues and eigenvectors in linear algebra.
  • Familiarity with the determinant and characteristic polynomial concepts.
  • Basic proficiency in using mathematical notation and operations.
NEXT STEPS
  • Study the geometric interpretation of eigenvalues and eigenvectors in 3D rotations.
  • Learn how to compute eigenvalues using the characteristic polynomial det(A - λI).
  • Explore the properties of rotation matrices in three-dimensional space.
  • Investigate complex eigenvalues and their implications in linear transformations.
USEFUL FOR

Students studying linear algebra, particularly those focusing on matrix transformations and eigenvalue problems, as well as educators teaching these concepts in a classroom setting.

concon
Messages
64
Reaction score
0

Homework Statement


The matrix A transforms space by rotating counterclockwise around z axis by ∏/4.

-What is A?
-Find a unit vector s.t. Au=u
(make sure the first nonzero is positive)
-for what λ's does Au = λu? write answer as a set {a,b,...}


Homework Equations



Unit vector u = x/norm(x)




The Attempt at a Solution



So I already found A :

[ sqrt2/2 -(sqrt2/2) 0
sqrt2/2 sqrt2/2 0
0 0 1]

which is correct.

How do I find u?

I think once I find u do I follow the process associated with finding eigenvalues
by using det(A-λI) to find λ's?
 
Physics news on Phys.org
concon said:

Homework Statement


The matrix A transforms space by rotating counterclockwise around z axis by ∏/4.

-What is A?
-Find a unit vector s.t. Au=u
(make sure the first nonzero is positive)
So I already found A :

[ sqrt2/2 -(sqrt2/2) 0
sqrt2/2 sqrt2/2 0
0 0 1]

which is correct.

How do I find u?
Consider the equation ##Au = u##. This means that ____ is an eigenvalue of ##A## and ____ is a corresponding eigenvector. (Fill in the blanks.)
 
jbunniii said:
Consider the equation ##Au = u##. This means that ____ is an eigenvalue of ##A## and ____ is a corresponding eigenvector. (Fill in the blanks.)

This seems like it might be wrong, but I did the usual procedure for finding eigenvalues and got
λ = sqrt(1/2) + sqrt(2)/2
Is this right? I think I might have solved the equation wrong?
 
concon said:
This seems like it might be wrong, but I did the usual procedure for finding eigenvalues and got
λ = sqrt(1/2) + sqrt(2)/2
Is this right? I think I might have solved the equation wrong?
That's one of the eigenvalues, assuming you meant ##\sqrt{1/2} + i \sqrt{1/2}##. (It's a complex number.) But there are two others.

The equation ##Au = u## tells you what one of the eigenvalues and eigenvectors must be.
 
Last edited:
By the way, there's an easy geometric interpretation that should be helpful: what vectors are unaffected by rotation around the z axis?
 
jbunniii said:
By the way, there's an easy geometric interpretation that should be helpful: what vectors are unaffected by rotation around the z axis?

Just thinking, but does that mean that 1 must be one of the eigenvalues?

We haven't been over this in class so I'm just guessing, but is a zero vector unaffected by rotation?
 
concon said:
Just thinking, but does that mean that 1 must be one of the eigenvalues?

We haven't been over this in class so I'm just guessing, but is a zero vector unaffected by rotation?
Yes, a zero vector is unaffected by rotation, but a zero vector is also unaffected by any linear transformation (matrix multiplication), so it doesn't give us much information. For this reason, eigenvectors are defined to be nonzero vectors satisfying ##Av = \lambda v## for some ##\lambda##.

What other vectors are unaffected by rotation around the z axis?
 
jbunniii said:
Yes, a zero vector is unaffected by rotation, but a zero vector is also unaffected by any linear transformation (matrix multiplication), so it doesn't give us much information. For this reason, eigenvectors are defined to be nonzero vectors satisfying ##Av = \lambda v## for some ##\lambda##.

What other vectors are unaffected by rotation around the z axis?

Wouldn't the vectors e1,e2,e3= {(1,0,0),(0,1,0),(0,0,1)} be unaffected?
 
concon said:
Wouldn't the vectors e1,e2,e3= {(1,0,0),(0,1,0),(0,0,1)} be unaffected?
Well, ##e_1## points in the direction of the positive x axis. Is the x-axis affected by rotation around the z axis?
 
  • #10
jbunniii said:
Well, ##e_1## points in the direction of the positive x axis. Is the x-axis affected by rotation around the z axis?
I think that yes it would have to be affected now that I think about it.So then should u = (0,0,1) since e3 points in direction of z?
 
  • #11
concon said:
So then should u = (0,0,1) since e3 points in direction of z?
Exactly.

In three dimensional space, there is always one and only one axis that isn't affected by a non-trivial (i.e., non-identity) rotation. That's the rotation axis.
 
  • #12
OK, that gives you one eigenvalue (1) and corresponding eigenvector ([0, 0, 1]). And the eigenvector is already scaled so it is a unit vector, as requested in the problem statement. So that takes care of the second question, which was:
Find a unit vector s.t. Au=u
(make sure the first nonzero is positive)
Next step is to find the other two eigenvalues:
for what λ's does Au = λu? write answer as a set {a,b,...}
 
  • #13
for what λ's does Au = λu? write answer as a set {a,b,...}
Actually, that question is worded rather poorly. It could be interpreted as referring to the ##u## from the previous part, in which case of course only ##\lambda = 1## is correct and the question seems pointless.

But I interpret it to mean "for what ##\lambda##'s is there a nonzero ##u## such that ##Au = \lambda u##?" In other words, find all of the eigenvalues. Probably best to check with your instructor just to make sure.
 
  • #14
jbunniii said:
Actually, that question is worded rather poorly. It could be interpreted as referring to the ##u## from the previous part, in which case of course only ##\lambda = 1## is correct and the question seems pointless.

But I interpret it to mean "for what ##\lambda##'s is there a nonzero ##u## such that ##Au = \lambda u##?" In other words, find all of the eigenvalues. Probably best to check with your instructor just to make sure.

yes that is what the professor meant. So we already have 1 as eigenvalue. The question specificies that only real values of λ to be included. Earlier in the thread I solved for the eigenvalues and got
λ= sqrt(1/2) + isqrt(1/2) which isn't a real number right?
So should answer just be{1}?
 
  • #15
concon said:
yes that is what the professor meant. So we already have 1 as eigenvalue. The question specificies that only real values of λ to be included. Earlier in the thread I solved for the eigenvalues and got
λ= sqrt(1/2) + isqrt(1/2) which isn't a real number right?
So should answer just be{1}?
Yes, if only real numbers are allowed then the only eigenvalue is 1.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
5
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
4
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K