Max Acceleration for Truck w/Crate & CoFriction

Click For Summary
SUMMARY

The maximum acceleration of a 5228 kg flatbed truck with a 226 kg crate, given a static coefficient of friction of 0.27, can be calculated using the formula f=ma. The gravitational force acting on the truck and crate is 5228 kg x 9.8 m/s² and 226 kg x 9.8 m/s², respectively. To determine the maximum horizontal acceleration without the crate slipping, one must consider the frictional force, which is the product of the static coefficient of friction and the normal force acting on the crate. The correct approach involves calculating the maximum frictional force and equating it to the product of the total mass and acceleration.

PREREQUISITES
  • Understanding of Newton's Second Law (f=ma)
  • Knowledge of static coefficient of friction
  • Basic principles of forces acting on objects
  • Ability to perform calculations involving mass and acceleration
NEXT STEPS
  • Calculate the maximum frictional force using the static coefficient of friction.
  • Learn how to apply Newton's Second Law in horizontal motion scenarios.
  • Explore the relationship between normal force and frictional force.
  • Study real-world applications of friction in vehicle dynamics.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators teaching concepts related to forces and motion.

rmalski
Messages
13
Reaction score
0

Homework Statement

[/B]A 5228 kg flatbed truck has a 226 kg crate resting on the level bed. If the static coefficient of friction is 0.27, what is the maximum acceleration the truck can achieve without the crate slipping off?

Homework Equations

[/B]f=ma

The Attempt at a Solution


i believe i need to find the force on each object. it would be 5228 x 9.8 and 226 x 9.8 but i am stuck there, especially with the static coefficient of friction. i do not understand that at all
 
Physics news on Phys.org
The forces you mention are from gravity. Works in a vertical direction. But we can assume there is no vertical acceleration. So there must be more forces at work.
Acceleration is probably in a different direction (I don't spoil the exercise if I say: horizontal). How do you bring in a force that works in a horizontal direction ?
 
to find the horizontal force would you have to multiply the mass by the coefficient of friction?
 
Coëfficiënt of friction is dimensionless: it is the ratio of (the magnitude of) two forces. Which ones ?
 
the friction force and applied force?
 
No.

Physics isn't a guessing game. What have you learned about this subject ?
 

Similar threads

Replies
6
Views
2K
Replies
3
Views
4K
  • · Replies 10 ·
Replies
10
Views
5K
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
4
Views
1K
Replies
8
Views
4K