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[SOLVED] Max angle of incidence...help!
A 1-cm-thick layer of water stands on a horizontal slab of glass. Light from a source within the glass is incident on the glass-water boundary. What is the maximum angle of incidence for which the light ray can emerge into the air above the water? (Give your answer in degrees.)
Isn't this just theta = sin^-1 * (1.33/1.5) = 62.46 degrees but that's not right. And I probably need to do something with the 1 cm thick layer of water but I don't know what?
Homework Statement
A 1-cm-thick layer of water stands on a horizontal slab of glass. Light from a source within the glass is incident on the glass-water boundary. What is the maximum angle of incidence for which the light ray can emerge into the air above the water? (Give your answer in degrees.)
Homework Equations
The Attempt at a Solution
Isn't this just theta = sin^-1 * (1.33/1.5) = 62.46 degrees but that's not right. And I probably need to do something with the 1 cm thick layer of water but I don't know what?