Max Angle of Mass on Incline Surface

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SUMMARY

The discussion centers on the calculation of the maximum angle of a mass on an incline surface, where the tangent of the angle (tan(𝜃)) is given as 0.67. The calculated angle using arctan(0.67) results in approximately 33.822 degrees, contradicting the suggested answer of 42 degrees. Further analysis reveals that arcsin(0.67) equals 42 degrees, indicating that the suggested answer is indeed incorrect. Participants agree that the discrepancy likely stems from a typographical error in the suggested answer.

PREREQUISITES
  • Understanding of trigonometric functions, specifically tangent and arcsine.
  • Familiarity with free-body diagrams in physics.
  • Basic knowledge of angle calculations and conversions.
  • Ability to interpret and analyze mathematical problems involving inclines.
NEXT STEPS
  • Review the principles of trigonometry, focusing on tangent and arcsine functions.
  • Study free-body diagram construction and analysis for inclined surfaces.
  • Explore common errors in angle calculations and how to identify them.
  • Consult physics textbooks or resources on forces on inclined planes for deeper understanding.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone involved in mechanics or engineering who requires clarity on trigonometric applications in real-world scenarios.

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Homework Statement
A brick with a mass of 2.3 kg is at rest on a rough surface that is at a slope that makes an angle
𝜃 above the horizontal, as shown in the diagram. If the slope becomes any steeper, the brick will start to slide downward along the slope. The coefficient of static friction of the brick with the surface is 0.67. What value must 𝜃 be less than for the brick to remain at rest?
Relevant Equations
mu = tan(theta)
Hello,

I've worked through the free-body diagram to compute the answer:

tan(𝜃) = 0.67
𝜃 = arctan(0.67) = 33.822...

The answer is supposed to be approximately 42. Yet, tan(42) is not 0.67, is the suggested answer wrong?
 
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Well, ##\arcsin(0.67) = 42## degrees. So, the answer looks wrong.
 
Agreed. It looks like the suggested answer of 42° is wrong. Can you attach an image of the problem statement diagram, just in case there is something else going on?
 
Sure, here is the diagram:

1644454548109.png

Thanks.
 
Okay, I think we agree the suggested answer is a typo. Can you check with your TA/Prof?
 
Sure, thanks.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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