Maxima, minima, and the mvt application

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SUMMARY

The discussion centers on applying the Mean Value Theorem (MVT) to determine the interval over which the function f(x) is increasing, given the conditions f''(x) ≥ -1 and f'(1) = 3. The conclusion drawn is that since f'(x) ≥ -x + 4, the function is definitely increasing for x values less than 4. This analysis utilizes the relationship between the second derivative and the first derivative to establish the behavior of the function.

PREREQUISITES
  • Understanding of the Mean Value Theorem (MVT)
  • Knowledge of derivatives, specifically first and second derivatives
  • Familiarity with inequalities involving functions
  • Basic calculus concepts, including intervals of increase and decrease
NEXT STEPS
  • Study the Mean Value Theorem and its applications in calculus
  • Learn how to analyze the behavior of functions using first and second derivatives
  • Explore inequalities in calculus and their implications on function behavior
  • Practice problems involving intervals of increase and decrease for various functions
USEFUL FOR

Students preparing for calculus exams, educators teaching derivative concepts, and anyone looking to strengthen their understanding of function behavior through calculus principles.

T Botha
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Hi there

I'm prepping for a big test tomorrow and I'm really struggling with this question:If f′′(x)≥−1, x belongs to (−15,15), and f′(1)=3, find the interval over which x is definitely increasing.I'm struggling with substitution because I just don't seem to have enough values. Is there a formula that gives an answer? Please let me know.

:( this is making me so sad.
 
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Since f''(x)\ge -1, f'(x)\ge -x+ C. Since f'(1)= 3, we know that C can be as large as 4. If f'(x)\ge -x+ 4 it will be positive for x less than 4.
 

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