MHB Maxima, minima, and the mvt application

Click For Summary
To determine the interval where the function is definitely increasing, given that f''(x) ≥ -1 and f'(1) = 3, we can derive that f'(x) ≥ -x + 4. This means that f'(x) remains positive for values of x less than 4. Thus, the function is increasing on the interval (-15, 4). The discussion highlights the importance of understanding the relationship between the second and first derivatives in applying the Mean Value Theorem. Overall, the key takeaway is that the function is guaranteed to be increasing up to x = 4.
T Botha
Messages
1
Reaction score
0
Hi there

I'm prepping for a big test tomorrow and I'm really struggling with this question:If f′′(x)≥−1, x belongs to (−15,15), and f′(1)=3, find the interval over which x is definitely increasing.I'm struggling with substitution because I just don't seem to have enough values. Is there a formula that gives an answer? Please let me know.

:( this is making me so sad.
 
Last edited:
Mathematics news on Phys.org
Since f''(x)\ge -1, f'(x)\ge -x+ C. Since f'(1)= 3, we know that C can be as large as 4. If f'(x)\ge -x+ 4 it will be positive for x less than 4.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K