Maximal Elements in a Bounded Set

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ertagon2
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Could someone please check these questions? Please correct them if necessary, with an explanation if you could.
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  • Quiz table of five set-theory and real-analysis questions with selected radio answers: countable or uncountable classification of three sets, supremum of two subsets of R, which of four sets is bounded above but not below, and true or false statements about bounded subsets of R and Q.
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Hi ertagon2,

Everything looks OK, except 5b. Think about the set $\displaystyle\left\{1-\frac{1}{n+1}\:\bigg|\: n\in\mathbb{N}\right\}$.
 
I agree with everything except 5.2. Consider an open interval.
 
castor28 said:
Hi ertagon2,

Everything looks OK, except 5b. Think about the set $\displaystyle\left\{1-\frac{1}{n+1}\:\bigg|\: n\in\mathbb{N}\right\}$.

I don't think I understand. Can you elaborate?
 
ertagon2 said:
I don't think I understand. Can you elaborate?
Hi ertagon2,

This is the set $\displaystyle S=\left\{0,\frac12,\frac23,\frac34,\ldots\right\}\subset\mathbb{Q}$. This set is bounded above (by $1$). In fact, $1$ is the least upper bound of $S$, but it is not an element of $S$.

No element of $S$ can be maximal, because, for each element $\left(1 - \dfrac{1}{n+1}\right)\in S$, $\left(1 - \dfrac{1}{n+2}\right)$ is greater and also an element of $S$.