Maximizing Circular Motion Experiment Accuracy with Horizontal Tension Force

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SUMMARY

The discussion centers on maximizing the accuracy of a circular motion experiment involving an eraser spun horizontally on a string. It is established that for optimal accuracy, the tension force (Ft) must remain horizontal. As the frequency of revolution increases, the angle of droop (A) between the tension force and the vertical force changes, impacting accuracy. A free body force diagram is essential to derive the relationship between angle A and frequency, utilizing the equation F=ma to analyze the forces involved.

PREREQUISITES
  • Understanding of circular motion dynamics
  • Familiarity with free body diagrams
  • Knowledge of trigonometric functions (cosine and sine)
  • Basic grasp of Newton's second law (F=ma)
NEXT STEPS
  • Study the derivation of tension force in circular motion
  • Learn about the relationship between frequency and angular displacement
  • Explore the impact of varying tension on circular motion accuracy
  • Investigate advanced applications of free body diagrams in physics experiments
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Physics students, educators, and experimenters focusing on circular motion dynamics and accuracy in physical experiments.

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Homework Statement



For an experiment involving spinning an eraser horizontally on the end of a string. For the greatest accuracy in this experiment, the tension force on the eraser should be horizontal. In this context, assuming all other variables are constant, what happens to the accuracy as the frequency of the revolution increases?

Homework Equations





The Attempt at a Solution



I think that the accuracy should increase as frequency increases. I know that you have to deal with the angle between the Ft and Ft cos forces. but I am not sure how to prove it
 
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You could find the formula relating the angle of droop A to the frequency by beginning with a free body force diagram for the object in circular motion. Be sure to show the string at angle A so you get cos(A) and sin(A) in some of the force expressions. F=ma.
 

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