Horizontal Circular Motion Problem

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SUMMARY

The discussion centers on the implications of increasing the frequency of revolution in a horizontal circular motion scenario involving a stopper attached to a pole via a string. The equation Fnet = 4π²mrf² is used to analyze the net force in uniform circular motion. As frequency increases, the horizontal motion becomes more pronounced, leading to a decrease in the vertical component of tension, which theoretically enhances accuracy. However, confusion arises regarding the constancy of the radius 'r' while frequency changes, suggesting that holding 'r' constant contradicts the principles of circular motion.

PREREQUISITES
  • Understanding of uniform circular motion principles
  • Familiarity with the equation Fnet = 4π²mrf²
  • Knowledge of tension forces in circular motion
  • Basic grasp of frequency and its relationship to radius in circular dynamics
NEXT STEPS
  • Explore the relationship between frequency and radius in circular motion
  • Study the effects of tension on circular motion accuracy
  • Learn about the dynamics of horizontal circular motion in physics
  • Investigate the implications of variable constraints in motion equations
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators seeking to clarify concepts related to tension and frequency in circular dynamics.

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Homework Statement


A stopper is being twirled around(horizontal circular motion), that is attached to a pole with a string.
What happens to the accuracy of Fnet = 4pi^2mrf^2(uniform circular motion equation) as the frequency of revolution of the stopper increases(assuming other variables of kept constant)?

Homework Equations


Fnet = 4pi^2mrf^2

The Attempt at a Solution


As the frequency of revolution increases, the motion of the stopper becomes more horizontal, which means the force of tension comes closer to acting parallel to the horizontal. Since the angle between the string and the horizontal decreases, the vertical component of tension decreases, which results in greater accuracy.
 
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No, that's not correct, but I don't understand how the frequency can change without 'r' changing. As the frequency increases, the horizontal radius must get bigger, so I'm not sure what the problem means by saying that the other variables remain constant. You'd be way off if you held r constant in your calculations, if that's what it means.
 

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