Maximizing Efficiency: Solving Problems with Ease

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To determine the energy expended by a 56.40 kg person ascending 20.60 m, the relevant equation is work = mgh, where g is the acceleration due to gravity. Given the efficiency of muscle operation is approximately 18.50 percent, the actual energy input required can be calculated using the efficiency formula: efficiency = work out/work in. This means the work done against gravity (mgh) must be divided by the efficiency to find the total energy expenditure. Thus, the problem emphasizes the importance of understanding both mechanical work and efficiency in calculating energy use during physical activities.
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Homework Statement
Efficiency is defined as work-out/work-in. Muscles operate with an efficiency of about 18.50 percent in converting energy internally into work externally. Accordingly, how much energy will be expended by a 56.40 kg person in the process of ascending several flights of stairs to a height of 20.60 m?
Relevant Equations
mgh
How to use efficiency in this problem?
 
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robotman said:
Homework Statement:: Efficiency is defined as work-out/work-in. Muscles operate with an efficiency of about 18.50 percent in converting energy internally into work externally. Accordingly, how much energy will be expended by a 56.40 kg person in the process of ascending several flights of stairs to a height of 20.60 m?
Relevant Equations:: mgh

How to use efficiency in this problem?
How much mechanical work has to be done to raise a mass m by height h?
 
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Hello again,

##mgh## is not a cure-all 😁 , but here $$ \text {work } = mgh $$ is indeed useful !
robotman said:
How to use efficiency in this problem?
use $$\text {efficiency} \equiv {\text {work out}\over\text {work in}} $$
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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