Maximum Angle for Non-Null Initial Velocity of Billiard Ball Hit by Cue

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Homework Help Overview

The discussion revolves around a physics problem involving a billiard ball of mass M and radius R, which is struck by a cue, resulting in an impulse J. The objective is to determine the maximum angle at which the ball can be hit such that its initial velocity is not null. The problem involves concepts of impulse, static friction, and rotational dynamics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the definitions of impulse and its components, questioning how to relate the angle θ to the ball's initial velocity. There are discussions about the implications of static friction and the conditions under which the ball may or may not move after being struck. Some participants express confusion about the wording of the problem and the meaning of "null velocity."

Discussion Status

The discussion is ongoing, with participants providing insights and corrections to each other's reasoning. Some have suggested that the problem's wording may be ambiguous, particularly regarding whether "null velocity" refers to translational or rotational motion. There is a general sense of exploration as participants attempt to clarify the physics involved.

Contextual Notes

Participants note that the problem may be constrained by the definitions of impulse and friction, as well as the initial conditions of the billiard ball being at rest before being struck. There is also mention of the need to distinguish between applied and effective impulses, which adds to the complexity of the problem.

  • #31
You have four conditions that must be satisfied if "null velocity" means no translational velocity and no rotational velocity:
(1) Net horizontal linear impulse = 0
(2) Net rotationall impulse = 0
(3) Net vertical impulse = 0
(4) ##f \leq \mu K##

The first two already restrict ##\theta## to one value.
Then, imposing the last two conditions restricts the allowed values of ##\mu##.

The fact that the problem statement makes no mention of a restriction on ##\mu## is just another oddity of the wording of the problem.
 
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  • #32
TSny said:
You have four conditions that must be satisfied if "null velocity" means no translational velocity and no rotational velocity:
(1) Net horizontal linear impulse = 0
(2) Net rotationall impulse = 0
(3) Net vertical impulse = 0
(4) ##f \leq \mu K##

The first two already restrict ##\theta## to one value.
Then, imposing the last two conditions restricts the allowed values of ##\mu##.

The fact that the problem statement makes no mention of a restriction on ##\mu## is just another oddity of the wording of the problem.

So, by your logic, I have μ \geq sqrt(2) /(2K)
But I know what (1) -> Jsinθ=K, hence μ \geq 1 /J (2)
All the values of μ satisfying (2) are good, and there's only one possible value for θ.
 
  • #33
anon90 said:
So, by your logic, I have μ \geq sqrt(2) /(2K)

How did you get this? Note that ##\mu## should be dimensionless.
 
  • #34
TSny said:
How did you get this? Note that ##\mu## should be dimensionless.
Right.
f≤μsK=μsJsinθ

Together with θ= 45° and Jcosθ−f=0, I get μ \geq 1
 
  • #35
OK, that's what I got, too.
 
  • #36
TSny said:
OK, that's what I got, too.
So, in the end, the two conditions should be
μ≥1
θ=45°
So the trick with this kind of problems is to figure out which forces can be though as impulsive in that laps of time, and then you just draw the fbd and solve it. Am I forgetting about anything else?
 
  • #37
I think that's essentially it.
 
  • #38
TSny said:
I think that's essentially it.
I see, thank you for your help and merry Christmass.
 
  • #39
Thanks. Merry Christmas to you, too.
 

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