# Maximum height of baseball, given total flight time.

• JP123
In summary, the question is asking for the maximum height reached by a baseball with a flight time of 7 seconds, ignoring air resistance. To solve this, the equations 1 and 5 of the constant acceleration equations can be used. The initial upward velocity is 34.3 seconds and the answer for maximum height reached is 60.03m. To find this, the initial vertical velocity can be used in one of the 5 equations that include displacement, along with the final velocity (zero), time (3.5 seconds going up, 3.5 seconds coming down), and acceleration (-9.8m/s^2).

## Homework Statement

The question i need to answer is: A baseball has a flight time of 7 seconds. What maximum height did it reach? (ignore air resistance.)

## Homework Equations

I need to use equation 1 and equation 5 of the constant acceleration equations.

## The Attempt at a Solution

I have figured out the initial upward velocity to be 34.3 seconds and now i don't know where to go from here! The answer for maximum height reached is 60.03m but i don't know how to get to this number. Please help!

Since every list of equations is different, we have no idea which equations are "1" and "5."

I am assuming this problem is for a straight up flight. What is the instantaneous velocity at the top of the path? If the entire flight took 7 seconds, how long did it take to get to the top? Do you know the rate of acceleration? Do you know three of the variables for the flight to the top of the path? (yes)

If the upward initial velocity is 34.3 seconds, you might need more than just a tweak to finish this problem.

JP123 said:

## Homework Statement

The question i need to answer is: A baseball has a flight time of 7 seconds. What maximum height did it reach? (ignore air resistance.)

## Homework Equations

I need to use equation 1 and equation 5 of the constant acceleration equations.

## The Attempt at a Solution

I have figured out the initial upward velocity to be 34.3 seconds and now i don't know where to go from here! The answer for maximum height reached is 60.03m but i don't know how to get to this number. Please help!

once you have that initial vertical velocity, you can use which ever of the 5 equations that include displacment, since you know the initial vel, the final vel [zero - it is at maximum height] the time [3.5 seconds going up, 3.5 coming back down], and the acceleration [9.8 down]