Maximum Height of Vertically Thrown Rock

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SUMMARY

Brad tosses a rock vertically at an initial velocity of 33.4 m/s. After 2.1 seconds, the correct final velocity is calculated using the equation V = Vo + at, where 'a' is -9.8 m/s² due to gravity. The user initially miscalculated the final velocity as 54 m/s but corrected it by applying the negative acceleration. To find the maximum height of the rock, the user should utilize the equation V² = Vo² + 2a(X - Xo).

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  • Understanding of kinematic equations in physics
  • Knowledge of acceleration due to gravity (9.8 m/s²)
  • Familiarity with the concept of initial and final velocity
  • Ability to manipulate algebraic equations
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  • Learn how to apply the kinematic equation V² = Vo² + 2a(X - Xo) for maximum height calculations
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Homework Statement



Brad tosses a rock straight up at 33.4 m/s. What is the rock's velocity after 2.1 seconds?


Homework Equations



V=Vo+at
X=Xo+volt+1/2at^2
V^2=Vo2+2a(X-Xo)

The Attempt at a Solution



I used the first equation. V=33.4m/s+9.8(2.1) 9.8 being the acceleration due to gravity. The hint says 'Final velocity equals the initial velocity plus the product of acceleration due to gravity (g) multiplied by the time.' I kept getting the incorrect answer of 54m/s.
 
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When going up the pull of the Earth will retard it so put '-9.8'.
 
Thank You! I got the answer right! But what equation would I use to find the maximum height of the rock?
 
Last edited:

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