Maximum Horizontal Force for Two Blocks to Accelerate Without Slipping?

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The problem involves determining the maximum horizontal force that can be applied to a lower block (M_2) on a frictionless table, while an upper block (M_1) rests on it without slipping. The key equation derived is F_max = μg(M_1 + M_2), where μ is the coefficient of friction and g is the acceleration due to gravity. This equation ensures that the frictional force is sufficient to prevent slipping between the two blocks. The initial calculations suggest that the approach is correct, aligning with the physical principles involved. Overall, the solution effectively addresses the conditions for maintaining acceleration without slipping.
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Homework Statement



A block of mass M_1 rests on a block of mass M_2 which lies on a frictionless table. The coefficient of friction between the blocks is \mu. What is the maximum horizontal force which can be applied to the lower (M_2) block for the blocks to accelerate without slipping on one another?

Homework Equations




The Attempt at a Solution


The acceleration of the two blocks (assuming they're not slipping) is a = \frac{F}{M_1 + M_2}, and you want the upper block (M_1) to not slip, that is, the acceleration times M_1 must be less than or equal to the frictional force. When the blocks start slipping, M_1 a = \mu M_1 g where the frictional force holding the upper block is f = \mu M_1 g. This means that a = \frac{F_{max}}{M_1 + M_2} = \mu g, or F_{max} = \mu g (M_1 + M_2).

I'm not sure if this answer is right, but it makes intuitive sense when looking at the final equation. Thanks for any help!

[edit] Sorry, posted in wrong section. I can't find a delete button, but any help would still be appreciated
 
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Looks correct.
 

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