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## Homework Statement

Two blocks, each of mass m, are connected on a frictionless horizontal table by a spring of force constant k and equilibrium length L.

Find the maximum and minimum separation between the two blocks in terms of their maximum speed, v

_{max}, relative to the table. (The two blocks always move in opposite directions as they oscillate back and forth about a fixed position.)

## Homework Equations

Conservation of energy

## The Attempt at a Solution

K

_{i}+ U

_{i}= K

_{f}+ U

_{f}

K

_{i}= U

_{f}

(1/2)mv

_{max}

^{2}= (1/2)kx

^{2}

Solve for x and the (1/2) cancel.

So:

x = sqrt(mv

_{max}/k)

This gives the amount the string has stretched, so the distance between the blocks would be x + L which would result in:

Max Seperation = sqrt(mv

_{max}/k) + L.

When I type in the solution I get a message that his is incorrect because the maximum separation does not depend on v

_{max}.