Two blocks, each of mass m, are connected on a frictionless horizontal table by a spring of force constant k and equilibrium length L.
Find the maximum and minimum separation between the two blocks in terms of their maximum speed, vmax, relative to the table. (The two blocks always move in opposite directions as they oscillate back and forth about a fixed position.)
Conservation of energy
The Attempt at a Solution
Ki + Ui = Kf + Uf
Ki = Uf
(1/2)mvmax2 = (1/2)kx2
Solve for x and the (1/2) cancel.
x = sqrt(mvmax/k)
This gives the amount the string has stretched, so the distance between the blocks would be x + L which would result in:
Max Seperation = sqrt(mvmax/k) + L.
When I type in the solution I get a message that his is incorrect because the maximum separation does not depend on vmax.