Maximum Torque Calculation for a Given Force and Angle

[amy098yay]

Homework Statement

2. Homework Equations [/B]
I was given this info
r=1.5 m
d=3 m
F= 50
angle= 110 degrees

The Attempt at a Solution

T=Fsin
T= (1.5)(50)sin(110)
T=70 N

I attempted the solution^ to get (maximum) torque.

 

[amy098yay]

i am unsure if my answer is correct or not*

 

[SteamKing]

You need to specify units for all the given quantities.

The units of torque are not Newtons. What are they?

 

[amy098yay]

Homework Statement

2. Homework Equations [/B]
I was given this info
r=1.5 m
d=3 m
F= 50 N
angle= 110 degrees

The Attempt at a Solution

T=Fsin
T= (1.5)(50)sin(110)
T=70 J (joules)

I attempted the solution^ to get (maximum) torque.

 

[SteamKing]

Although mathematically torque and work have the same units, the convention is to use units of F*L when talking about torque, and joules when talking about work.

 

[amy098yay]

thank you for notifying me about the units being used in this problem, so how would i go about getting MAXIMUM TORQUE?

 

[SteamKing]

thank you for notifying me about the units being used in this problem, so how would i go about getting MAXIMUM TORQUE?

Change the angle of application of the force.

 

[amy098yay]

would it be 180-110=10 degrees
so
T=Fsin
T= (1.5)(50)sin(10)
T=13.0 J (joules) ?

 

[SteamKing]

would it be 180-110=10 degrees

Are you sure about this calculation?

so
T=Fsin
T= (1.5)(50)sin(10)
T=13.0 J (joules) ?

Think about it like this For what angle is the sine a maximum?

 

[amy098yay]

90?

T=Fsin
T= (1.5)(50)sin(90)
T=75 (joules)

 

[CWatters]

You posted the same question twice...
https://www.physicsforums.com/threads/torque-problem-confused.800504/

 

[gneill]

CWaters is correct, this thread duplicates a question in another thread. This thread is closed.