Calculate Maximum Velocity of Girl on Swing

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SUMMARY

The maximum velocity of a girl on a swing, suspended from a 10m rope, occurs at the lowest point of her swing, which is 1m above the ground. Using the principle of conservation of energy, the maximum velocity can be calculated using the formula v = √(2gh), where h is the height difference. In this case, h is 1m, leading to a maximum velocity of approximately 4.43 m/s. The discussion emphasizes the importance of understanding potential and kinetic energy in the context of pendulum motion.

PREREQUISITES
  • Understanding of potential energy (PE = mgh)
  • Understanding of kinetic energy (KE = 1/2 mv²)
  • Basic knowledge of pendulum motion and energy conservation
  • Familiarity with gravitational acceleration (g = 9.81 m/s²)
NEXT STEPS
  • Study the conservation of mechanical energy in pendulum systems
  • Learn how to derive the period of a simple pendulum using the formula T = 2π√(L/g)
  • Explore the effects of different swing angles on maximum velocity
  • Investigate the relationship between potential energy and kinetic energy in various mechanical systems
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of pendulum motion and energy conservation principles.

  • #31
this book I have says stuff like potential energy goesinto kinetic energy if you refer to the conservation of mechanical energy.
 
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  • #32
Yes but it says what is her maximum velocity:

So v=sqrt 2gh @ 1m = 4.43 m/s but v=sqrt 2gh @ 2m = 6.26 m/s ... (so this does not make sense to me...)
 
  • #33
the height is the y direction between the heighest point and the lowest point. does that make sense?
 
  • #34
yes... get it now... fwwwww lol... thanks for all you help!
 
  • #35
oh! well then you'd think that technically there still is a potential energy at the lowest point, since it's 1 meter above ground, which means v=sqrt2ghfinal - sqrt2ghinitial, but that's incorrect, because it violates the law of conservation of energy. but hm...maybe h=2meters, because it's 2 meters from the ground. I'm really sorry if you are confused. I am too!
 
  • #36
Rayquesto said:
oh! well then you'd think that technically there still is a potential energy at the lowest point, since it's 1 meter above ground, which means v=sqrt2ghfinal - sqrt2ghinitial, but that's incorrect, because it violates the law of conservation of energy. but hm...maybe h=2meters, because it's 2 meters from the ground. I'm really sorry if you are confused. I am too!

This problem has little to do with the actual Potential energy, and everything to do with the CHANGE in Potential energy.
In all problems, we get to set where zero height is, and invariably we choose either the lowest point, the highest point, the starting point or the finishing point.

For example

Lowest point - A swing or similar

Highest point - a satellite [rare]

Start point - projectile motion

Finish Point - roller coaster.
 
  • #37
Rayquesto said:
the height is the y direction between the heighest point and the lowest point. does that make sense?

On in proper description: The h value [change in height] is the difference between highest point and lowest point.
 

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