Hi everyone! my problem: since every simple function is bounded, we at once know, that either is our function f, cause: [tex] - \epsilon + g(x) <= f(x) <= \epsilon + g(x)[/tex], so that's obviously not the problem here. this whole measure stuff doesn't get into my intuition and I don't have any idea how to try to solve this task. if i knew, that for each [tex]\epsilon[/tex] i could get a measurable function g, it would be obvious, that f is measurable too [wouldn't it?], but can i really always have a measurable function g? i would be very grateful for any hints. hope my english isnt terrible enough to disturb the sense of this post. rahl.