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bolzano
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Hi, I was wondering whether if ∫f×g dμ=∫h×g dμ for all integrable functions g implies that f = h?
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Measure theory is a branch of mathematics that deals with the concept of measuring sets and their properties. It provides a rigorous foundation for integration, which is a mathematical concept used to find the area under a curve or the volume under a surface. In measure theory, integrals are defined as the limit of a sequence of approximations, which allows for a more general and precise definition than in traditional calculus.
Riemann integration is the traditional method taught in calculus, where the area under a curve is approximated by rectangles. Lebesgue integration is a more general and powerful form of integration that extends the concept to a wider range of functions. It uses a different approach to defining the integral, based on measure theory, and allows for the integration of more complex functions that may not have a traditional antiderivative.
Measure zero refers to a set that has no length, area, or volume, depending on the dimension of the space in which it exists. In measure theory, these sets are considered negligible and do not contribute to the overall measure of a larger set. This concept is important because it allows for the definition of integrals on more complex sets, such as fractals, where traditional methods of integration may fail.
The Lebesgue integral is used in probability theory to define the probability of an event occurring. In this context, the integral is known as the probability measure, and it assigns a number between 0 and 1 to a set of possible outcomes. This allows for a more rigorous and general treatment of probability, and it is a fundamental concept in the field of measure-theoretic probability.
Yes, the classic example is the Dirichlet function, which takes the value 1 on rational numbers and 0 on irrational numbers. This function is Riemann integrable because its set of discontinuities has measure zero, but it is not Lebesgue integrable because it does not satisfy the conditions required by the Lebesgue integral. This highlights the difference in scope and flexibility between Riemann and Lebesgue integration.