You are asked to measure the moment of inertia of a large wheel for rotation about an axis through its center. You measure the diameter of the wheel to be 0.740 m and find that it weighs 280 N. You mount the wheel, using frictionless bearings, on a horizontal axis through the wheel's center. You wrap a light rope around the wheel and hang a 8.00 kg mass from the free end of the rope. You release the mass from rest; the mass descends and the wheel turns as the rope unwinds. You find that the mass has a speed 5.00 m/s after it has descended 2.00m. What is the moment of inertia of the wheel for an axis perpendicular to the wheel at its center?
E initial = mgh
E final = 1/2mv^2 + 1/2[tex]I[/tex][tex]\omega^2[/tex]
The Attempt at a Solution
I tried using conservation of energy and then solving for [tex]I[/tex]
But I don't think that is the way to go.
Any help is appreciated, Thanks!