- #1

iancheung228

- 13

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## Homework Statement

I am currently doing a lab investigating the relationship between the moment of inertia and speed.

I have attached some pictures of my 'wheel' that is going to be rolled down a ramp. FYI i will be using a photogate to measure the time it takes the black strip to pass through. Initially, I thought the magnets were creating the 'hollow' part of the disc, but apparently i am wrong, and I am wondering how to calculate the moment of inertia of the magnet and then apply the moment of inertia to the equation mgh=1/2mv^2+I system (omega)^2.

## Homework Equations

MgH=v^2(m/2+Isystem/2r^2)

where M is the mass of the whole wheel system 0.369kg.

g is 9.8

H is the initial height on the ramp which is 0.105m

V is measured with a photogate ,0.10m/0.11746s= 0.85135m/s

radius of the circle is 8cm.

I of the system is (mr^2/2)+(mr^2/2)+8(mass of magnets (0.019kg(0.53m^2+2(0.078m^2))

where the mass of bgi wheel is 0.142kg and small wheel 0.074kg.

MgH=v^2(m/2+Isystem/2r^2)

where M is the mass of the whole wheel system 0.369kg.

g is 9.8

H is the initial height on the ramp which is 0.105m

V is measured with a photogate ,0.10m/0.11746s= 0.85135m/s

radius of the circle is 8cm.

I of the system is (mr^2/2)+(mr^2/2)+8(mass of magnets (0.019kg(0.53m^2+2(0.078m^2))

where the mass of bgi wheel is 0.142kg and small wheel 0.074kg.