Mechanical energy and frames of reference.

1. Oct 26, 2012

InertialRef

1. The problem statement, all variables and given/known data

a)Suppose the chancellor of the university drops a 2.00 kg water balloon from the administration
building balcony 10.0 m above the ground. The chancellor takes the origin of his vertical axis
to be even with the balcony. A student standing on the ground below the chancellor decides
she would rather have the origin of her coordinate system be the ground at her feet.
b)Calculate the value of the gravitational potential energy of the balloon before it is dropped and
just as it hits the ground for each of the frames of reference.

chancellor frame:
PE bef= (2.00)(9.81)(0 m) = 0 J
PE aft= (2.00)(9.81)(10 m) = 196.2 J

student frame:
PE bef= (2.00)(9.81)(10 m) = 196.2 J
PE aft= (2.00)(9.81)(0) = 0 J

c)Calculate the value of the kinetic energy of the balloon before it is dropped and just as it hits the ground for each of the frames of reference.

chancellor frame:
KE bef= (0.5)(2.00)(0)^2 = 0
KE aft= (0.5)(2.00)(9.81*(√(20/9.81)))^2 = -196.2

I calculated for the final velocity using the principle kinematics equation.

student frame:
KE bef= 0
KE aft= -196.2

d)Calculate the total mechanical energy of the balloon before it is dropped and just as it hits the ground for each of the frames of reference.

chancellor frame:
TME bef=
TME aft=

student frame:
TME bef=
TME aft=

2. Relevant equations

KE = (0.5)m(v^2)
PE = mgh

3. The attempt at a solution

I've solved for most of it, since it was pretty simple, but I'm stuck at part d. Shouldn't total mechanical energy always be conserved? How is it that for the president, total mechanical energy isn't conserved? The total energy initially = 0, then it increases. Why does it do that?

I understand that when looked at from one frame of reference only, the total energy is conserved. But when looked at from two frames of references, total energy only appears to not be conserved, but it actually is. Is there some way to correct for this, or is the only way to see if mechanical energy is conserved is to observe such motion from one frame of reference?

2. Oct 26, 2012

Sourabh N

Firstly, how is the kinetic energy negative?

Secondly, in the frame of reference of the chancellor, the balloon's height is negative. Do you see why?

Does the potential energy increase or decrease when an object comes closer to the Earth's surface?

3. Oct 26, 2012

InertialRef

Whoops, sorry about that. Mixed up PE with KE, my mistake.

Yes, I can see why the balloon's height is negative. From the frame of reference of the student, the height is positive, so from the frame of reference of the chancellor, the height is negative. Potential energy decreases as it comes closer to the Earth's surface, but that's only if you take the frame of reference of the student, isn't it?

4. Oct 26, 2012

Sourabh N

Following your argument, PE aft in the chancellor's frame is changed, as below.

chancellor frame:
PE bef= (2.00)(9.81)(0 m) = 0 J
PE aft= (2.00)(9.81)(-10 m) = -196.2 J

No, potential energy varies, but CHANGE in potential energy is the same for both, since the only difference between the two frames is the zero of the potential energy.

5. Oct 26, 2012

InertialRef

So, would I be correct in saying that since the change in PE is equal to the change in KE, in both frames of reference, then this indicates that the energy is conserved and the only reason the two observers don't calculate the same values for mechanical energy is because the zero of the potential energy varies in each frame?