Mechanical Principles help please.

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Discussion Overview

The discussion revolves around calculating the effort required to raise a load using a Weston differential pulley block, including considerations of efficiency and work done against friction. Participants explore the necessary formulas and clarify terms related to the problem.

Discussion Character

  • Homework-related, Technical explanation

Main Points Raised

  • One participant, Joe, presents an initial calculation for the effort and work done, questioning the correctness of their units and approach.
  • Another participant suggests using specific formulas for velocity ratio and mechanical advantage, indicating that they have encountered similar problems in class.
  • There is a clarification about the meaning of "d" in the formulas, with one participant confirming it refers to diameter.
  • Joe expresses confusion about whether to use diameter or circumference in calculations, indicating a potential misunderstanding of the problem setup.
  • Another participant asserts that using diameters yielded correct answers in their calculations, suggesting consistency in their approach.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether to use diameter or circumference in the calculations, indicating a point of confusion. The discussion remains unresolved regarding the correctness of Joe's initial calculations.

Contextual Notes

There are unresolved assumptions regarding the definitions of terms and the application of formulas, particularly concerning the use of diameter versus circumference in the context of the pulley system.

crutts
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1. The top pulleys of a Weston differential pulley block have diameters of 210mm and 190mm. Determine the effort required to raise a load of 150kg if the efficency of the system is 35%.

What is the work done in overcoming friction when the load is raised through a height of 2.5m?





I did some working out and got:

effort = load/number of pulleys = 150/2 = 75 (what units?)

and work done= (150x9.8) x 2.5 = 3677.6 N/M

I did 150x9.8 to get Newtons.

Is this correct?


Cheers Joe
 
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you must work out using these formulas

i only no this as i did the same question in class

you need to work out the velocity ratio of the machine first

vr = 2 d1/(d1-d2)

then the mechanical advantage

effiency of the system = mechanical advantage/ velocity ratio x 100 %

you need to transpose this


effort of the machine = load / mechanical advantage

this is for the first part

second part is

wd = force x distance moved

then effiency of the system = work output/work input

you also need to transpose this
i no how you feel this is a hard subject and i am also finding it hard !
 
I take it d stands for diameter? Should it be this or should it be circumfrence?

Joe
 
d is the diameter of each pulley
 
Should I use diameter or circumfrence? As i seem to remember circumfrence being mentioned in class.
 
when i calculated these i used the diameters and the answers were correct compared to the answers i had.
 
Ok cheers.
 

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