MHB Mechanics- general motion in a straight line

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To calculate the total distance traveled by the robot over 10 seconds, sum the absolute distances moved in each time interval. From t=0 to t=2, the robot moves 2.56m away, then 0.81m back toward the starting position from t=2 to t=5. It moves away again by 0.81m from t=5 to t=8 and returns 2.56m to the starting position from t=8 to t=10. The total distance is 2.56m + 0.81m + 0.81m + 2.56m, resulting in a total distance of 6.74m. Understanding these calculations is essential for analyzing motion in mechanics.
Shah 72
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I don't understand how to find the distance that robot travels in 10s.
 
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t=0 to t=2 … the robot moves away from its starting position 2.56m

t=2 to t=5 … the robot moves back toward its starting position 0.81m

t=5 to t=8 … the robot moves away again from its starting position 0.81m

t=8 to t=10 … the robot moves back to its starting position 2.56m

total distance traveled by the robot would be … ?
 
skeeter said:
t=0 to t=2 … the robot moves away from its starting position 2.56m

t=2 to t=5 … the robot moves back toward its starting position 0.81m

t=5 to t=8 … the robot moves away again from its starting position 0.81m

t=8 to t=10 … the robot moves back to its starting position 2.56m

total distance traveled by the robot would be … ?
Thank you very much!
 
Thread 'Erroneously finding discrepancy in transpose rule'

Thread 'Erroneously finding discrepancy in transpose rule'

Obviously, there is something elementary I am missing here. To form the transpose of a matrix, one exchanges rows and columns, so the transpose of a scalar, considered as (or isomorphic to) a one-entry matrix, should stay the same, including if the scalar is a complex number. On the other hand, in the isomorphism between the complex plane and the real plane, a complex number a+bi corresponds to a matrix in the real plane; taking the transpose we get which then corresponds to a-bi...
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