Mechanism for reaction of C6H5NH3 with NaOH?

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The discussion focuses on the reaction mechanism of C6H5NH3 with NaOH to produce C6H5NH2. It highlights that C6H5NH3, which has a positively charged nitrogen, undergoes deprotonation by NaOH, resulting in a neutral amine, C6H5NH2. The process involves NaOH acting as a base to remove a proton, with water being formed as a byproduct. Additionally, the importance of including the counterion for the amine salt in the mechanism is noted. Understanding this reaction mechanism is crucial for accurately representing the transformation of the amine.
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Hello again!
I have a question regarding the reaction of C6H5NH3 with NaOH to make C6H5NH2. How would a mechanism be written to describe this process? I know that C6H5NH3 goes from having a positive charge on the nitrogen and after it reacts with NaOH, C6H5NH2 has a neutral charge but not sure how to write a mechanism to describe it. Would the NaOH just deprotonate C6H5NH3 and form H2O as a leaving group? Any help would be appreciated!
Thanks!
 
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Yeah, but you should include the counterion for the amine salt.
 
Thanks!
 
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