Melting ice using latent heat and heat of fusion

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SUMMARY

The discussion focuses on calculating the mass of ice at 2 degrees Celsius that can be melted by 100 J of heat using the equations for heat transfer. The relevant equations are q = mc(Δt) for specific heat and q = ml for heat of fusion. The specific heat of ice is 2.09 J/g-K, and the heat of fusion is 6.01 kJ/mol. The solution involves combining these equations and converting between grams and moles using the molecular weight of water (approximately 18 g/mol).

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  • Understanding of thermodynamics principles, specifically latent heat and heat of fusion
  • Familiarity with the specific heat capacity of substances
  • Knowledge of unit conversions between grams and moles
  • Proficiency in algebraic manipulation of equations
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  • Learn about the specific heat capacities of various substances
  • Explore the calculations involving heat transfer in thermodynamic processes
  • Practice converting between grams and moles using molecular weights
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Homework Statement



What quantity of ice at 2 deg Celsius can be melted by 100 J of heat?


Homework Equations



q = m c (delta) t (mass x specific heat x change in temp)
q = m l (mass x heat of fusion)

specific heat of ice = 2.09 j/g-K
heat of fusion = 6.01 kJ/mol

The Attempt at a Solution



I've tried to solve this problem by combining both equations for the same q such that
q = mc(delta)t + ml which rearranges to:
q = m (c delta t + l)

solving for m: m = q/ (c delta t + l)

The part I got stuck is when I tried to solve for m since m is in grams, and the heat of fusion is in moles. Is there another way to solve this or am I missing something?
Any help would be greatly appreciated
 
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You can use the molecular weight of water (~18g/mol) to convert between grams and moles.
 

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