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## Homework Statement

If 13.4 kJ of heat is added 1.00 kg of ice at 0ºC, how much ice will be melted

## Homework Equations

Change of Heat = mass*change of temperature*constant

change of heat fusion (water) = 333 J/g

change of heat water vapor = 2260 J/g

change of heat total = change of heat (state) + change of heat (temp change)

constant of water = 4.184 J/gºC

constant of ice = 2.1 J/gºC

## The Attempt at a Solution

(1000g)(2.1J/gºC)(?-0) + (13400g*333J/gºC)

Answer = 40g