# Melting Ice with a Carnot Engine

A Carnot heat engine uses a hot reservoir consisting of a large amount of boiling water and a cold reservoir consisting of a large tub of ice and water. In 5 minutes of operation of the engine, the heat rejected by the engine melts a mass of ice equal to 3.40×10^−2 kg.
Throughout this problem use L_f = 3.34x10^5 J/kg for the heat of fusion for water.

During this time, how much work W is performed by the engine?

I dont know where to start...any help please?

Related Introductory Physics Homework Help News on Phys.org
alphysicist
Homework Helper
Hi horsegirl09,

What is the efficiency of this engine? You are able to find a numerical value here.

Once you have that, how is the efficiency related to the work done?

I still dont see how i can get the efficiency without any temperatures or heat values

alphysicist
Homework Helper
You do have the temperatures: one reservoir is boiling water and the other reservoir is a mixture of ice and water. What efficiency does that give?

Tc=273 k Th= 373 k
n = 1- (Tc/Th)
n = 1- (273/373)
n = 1-.73
n = .27 or 27%

n= 1-Tc/Th = W/Qh
how do i get Qh to get W?

TMM
You know that the exhaust melts a certain amount of water, so from that you can find the heat lost.