- #1

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Throughout this problem use L_f = 3.34x10^5 J/kg for the heat of fusion for water.

During this time, how much work W is performed by the engine?

I dont know where to start...any help please?

- Thread starter horsegirl09
- Start date

- #1

- 16

- 0

Throughout this problem use L_f = 3.34x10^5 J/kg for the heat of fusion for water.

During this time, how much work W is performed by the engine?

I dont know where to start...any help please?

- #2

alphysicist

Homework Helper

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What is the efficiency of this engine? You are able to find a numerical value here.

Once you have that, how is the efficiency related to the work done?

- #3

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I still dont see how i can get the efficiency without any temperatures or heat values

- #4

alphysicist

Homework Helper

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- #5

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Tc=273 k Th= 373 k

n = 1- (Tc/Th)

n = 1- (273/373)

n = 1-.73

n = .27 or 27%

n = 1- (Tc/Th)

n = 1- (273/373)

n = 1-.73

n = .27 or 27%

- #6

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n= 1-Tc/Th = W/Qh

how do i get Qh to get W?

how do i get Qh to get W?

- #7

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You know that the exhaust melts a certain amount of water, so from that you can find the heat lost.

- #8

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thanks i got the answer!!

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