Work done by a Carnot Engine. Melting ice

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SUMMARY

The discussion revolves around calculating the work done by a Carnot engine that melts ice using boiling water as the hot reservoir and ice water as the cold reservoir. The user determined that the energy transferred to the cold reservoir, Qc, is 13.3 kJ, calculated using the heat of fusion of water (Hf = 333.55 kJ/kg) for 0.0400 kg of ice. To find the work done (W), the user needs to apply the Carnot efficiency equation and the relationship between Qh and Qc. The key equations discussed include W = Qh - Qc and the efficiency e = 1 - Tc/Th.

PREREQUISITES
  • Understanding of Carnot engine principles
  • Knowledge of thermodynamic equations, specifically W = Qh - Qc
  • Familiarity with the heat of fusion of water (Hf = 333.55 kJ/kg)
  • Basic concepts of thermal reservoirs and energy transfer
NEXT STEPS
  • Calculate the hot reservoir temperature (Th) using the Carnot efficiency formula
  • Learn about the implications of the Carnot cycle in thermodynamics
  • Explore the relationship between work done and heat transfer in thermodynamic systems
  • Investigate real-world applications of Carnot engines in energy efficiency
USEFUL FOR

Students studying thermodynamics, physics enthusiasts, and engineers interested in heat engine efficiency and energy transfer calculations.

The Real Simon

Homework Statement


The problem is that a Carnot contains Boiling water in the hot reservoir and ice water in the cold reservoir.
Given that 0.0400kg of ice is melted in 5 minutes, what is the amount of work done by the engine.

Homework Equations


Qh/Qc=Th/Tc
W=Qh-Qc
W=(1-Tc/Th)Qs
q=mHf
e=1-Tc/Th
e=W/Th
heat of fusion of water=Hf=333.55kJ/kg
I'm sure more are needed to solve it

3. The Attempt at a Solution

All I was able to solve is the energy transferred to the cold reservoir. q=0.0400kgx333.55kJ/kg=13.3kJ I think this is the Qc but really not sure.

Thanks for the help!
 
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The Real Simon said:
All I was able to solve is the energy transferred to the cold reservoir. q=0.0400kgx333.55kJ/kg=13.3kJ I think this is the Qc but really not sure.
Yes, that's ##Q_c##. You now need to find the work done by the Carnot engine.
 
Since you know Qc, you know 3 out of the 4 quantities in your first equation.
 

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