Melting Nickel Ball: Temperature & Radius Effects

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SUMMARY

The melting behavior of a nickel ball with radius r and temperature Tn in an ice block at temperature Ti is governed by several key factors including thermal diffusivity (κ), temperature difference (ΔT), gravitational acceleration (g), specific latent heat of melting for ice (L), and thermal conductivity of ice (λ). The derived formula for the distance melted into the ice is d = (ΔT λ r^4 g) / (κ^2 L). A nickel ball of 1 cm³ can ideally melt its own volume of ice for every 80°C above 0°C, but practical observations indicate that it melts approximately 3-4 times its volume due to significant heat loss, evidenced by steam production during the process.

PREREQUISITES
  • Understanding of thermal diffusivity (κ) and its role in heat transfer
  • Knowledge of specific latent heat of melting for ice (L)
  • Familiarity with thermal conductivity of materials, specifically ice (λ)
  • Basic principles of thermodynamics, including heat transfer and energy conservation
NEXT STEPS
  • Research the effects of thermal diffusivity on heat transfer in solids
  • Study the principles of blackbody radiation and its implications for thermal energy loss
  • Explore the specific heat capacities of various materials to compare melting behaviors
  • Investigate experimental methods for measuring thermal conductivity in ice and metals
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Physicists, materials scientists, and engineers interested in thermodynamics, heat transfer applications, and the melting processes of materials in thermal interactions.

Borek
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How far down can a nickel ball of radius r and temperature Tn melt into the ice block of temperature Ti? Watch the video and state your assumtpions...

 
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The distance should depend on the thermal diffusivity of the ball (κ), the temperature difference between the ball and ice (##\Delta T = T_n - T_i##), the gravitational acceleration constant (g), the specific latent heat of melting for ice (L), the thermal conductivity of the ice (λ), and the radius of the ball (r). A combination of these variables that has the dimension of length and is physically plausible is

## d = \frac{\Delta T λ r^4 g}{κ^2 L} ##

The distance may also involve the dimensionless ratio of the density of the ball to that of the ice.
 
Last edited:
Assume a ball of 1 cm3. The specific heat of nickle is 0.44 J/gK and its density is 8.9 g/mL, so it should release 3.9 J for each degree of celsius cooled. The heat of fusion of ice is 335 J/g and its density is 0.934 g/mL, so melting 1 mL of ice requires 312 J of energy. So, a ball ideally should be able to melt its own volume of ice for every 80oC above 0oC. Based on blackbody radiation curves, red hot objects tend to be ~600oC, which would correspond to melting ~ 7-8x the volume of the ball. In the video, the ball melts ~ 3-4x its size, indicating that a lot of the heat is lost (for example, you see a lot of steam produced, meaning that not all of the energy goes into melting the ice, and a good deal of thermal energy is probably lost when the water pours out of the side of the ice block).
 
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