A Merging Gravity with the other forces

[weirdoguy]

I don't see the incompatibility of QM with GR.......

Don't take it personal, but what you wrote there shows that you have no idea what you are talking about. $R$ is not a radius, and Einstein equation is not an algebraic equation, it's tensorial so you can't just simply divide by $g_{\mu\nu}$.

 

[VictorMedvil]

Don't take it personal, but what you wrote there shows that you have no idea what you are talking about. $R$ is not a radius, and Einstein equation is not an algebraic equation, it's tensorial so you can't just simply divide by $g_{\mu\nu}$.

Then what is that R?

 

[weirdoguy]

Scalar curvature. You should know that if you try to manipulate this equation.

 

[VictorMedvil]

but isn't scalar curvature just the two principal radii? where

are the principal radii of the surface. For example, the scalar curvature of the 2-sphere of radius r is equal to 2/r².

 

[weirdoguy]

Not in four dimensions. General definition is $R=R^\mu_{\phantom{\mu}\mu}$. You should really study some textbook on very basics before you try to learn about quantum gravity.

 

[VictorMedvil]

Not in four dimensions. General definition is $R=R^\mu_{\phantom{\mu}\mu}$. You should really study some textbook on very basics before you try to learn about quantum gravity.

The parameter r is a geometrical invariant of the hyperbolic space, and the sectional curvature is K = −1/r². The scalar curvature is thus S = −n(n − 1)/r². Explain this to me, from what I understand it is just a radius.

 

[weirdoguy]

from what I understand it is just a radius.

Then your understanding is flawed. As I said before $R=R^\mu_{\phantom{\mu}\mu}$, that is $R$ is a trace of Ricci tensor. Please get some textbook on general relativity and learn everything properly, not from random articles on the internet.