Merry Go Round (Centripetal Force)

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SUMMARY

The discussion centers on calculating the horizontal force required for Jackie, one of two twins on a frictionless merry-go-round, to avoid falling off. Jena exerts a force of 58.0 N while sitting 1.80 m from the center, leading to a calculated velocity of 1.89 m/s. The correct approach involves using angular velocity, resulting in Jackie needing to exert a force of 117.6 N while sitting 3.67 m from the center. The calculations confirm that both twins share the same angular velocity, necessitating different linear velocities due to their varying distances from the center.

PREREQUISITES
  • Understanding of centripetal force and its formula: F = m*v²/R
  • Knowledge of angular velocity and its relationship with linear velocity: ω = v/R
  • Familiarity with basic physics concepts such as mass, force, and acceleration
  • Ability to manipulate equations and perform unit conversions in physics
NEXT STEPS
  • Study the principles of centripetal acceleration and its applications in circular motion
  • Learn about angular momentum and its conservation in rotational systems
  • Explore real-world applications of frictionless surfaces in physics experiments
  • Investigate the effects of varying mass and radius on forces in circular motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators seeking to clarify concepts related to forces and motion in a practical context.

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Homework Statement



Two identical twins, Jena and Jackie, are playing one December on a large merry-go-round (a disk mounted parallel to the ground on a vertical axle through its center) in their school playground in northern Minnesota. Each twin has a mass of 29.0 kg. The icy coating on the merry-go-round surface makes it frictionless. The merry-go-round revolves at a constant rate as the twins ride on it. Jena, sitting a distance 1.80 m from the center of the merry-go-round, must hold on to one of the metal posts attached to the merry-go-round with a horizontal force of 58.0 N to keep from sliding off. Jackie is sitting at the edge, a distance 3.67 m from the center.

With what horizontal force must Jackie hold on to keep from falling off?

If Jackie falls off, what will be her horizontal velocity when she becomes airborne?


I attempted this problem but got the wrong answer. What I did first was

58N = 29kg*V^2
=========
1.80

V = 1.89 m/s

Fnet = m*v^2
---------
R

Fnet = (29kg)(1.89m/s)^2
--------------------
3.67

Fnet = 28.4N


What did I do wrong?
 
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1.89 m/s is not the velocity of Jack. Their angular velocities is the same.
And angular velocity ω = v/R.
So v1/R1 = v2/R2. So find v2.
 
So

1.89m/s
-------- = V2/3.67m
1.80 m

V2 = 3.8585 m/s ?

Then

Fnet = (29kg)(3.8585m/s)^2/3.67m = 117.6N ?
 
Yes. That is right.
 

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