Merry Go Round (Centripetal Force)

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Homework Help Overview

The problem involves two twins on a merry-go-round, focusing on the forces required to maintain their positions due to centripetal motion. The context includes concepts of frictionless surfaces and the relationship between linear and angular velocities.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the calculation of forces acting on the twins, particularly the horizontal force needed to prevent sliding off the merry-go-round. There is an exploration of angular velocity and its relationship to linear velocity, with attempts to derive the correct velocity for Jackie based on Jena's situation.

Discussion Status

Some participants have provided guidance on the relationship between angular and linear velocities, leading to further calculations. There appears to be a productive exchange regarding the correct approach to finding the forces involved, though no consensus on the final answer has been reached.

Contextual Notes

The problem is constrained by the assumption of a frictionless surface and the need to maintain circular motion, which raises questions about the forces acting on the twins at different distances from the center.

Chandasouk
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Homework Statement



Two identical twins, Jena and Jackie, are playing one December on a large merry-go-round (a disk mounted parallel to the ground on a vertical axle through its center) in their school playground in northern Minnesota. Each twin has a mass of 29.0 kg. The icy coating on the merry-go-round surface makes it frictionless. The merry-go-round revolves at a constant rate as the twins ride on it. Jena, sitting a distance 1.80 m from the center of the merry-go-round, must hold on to one of the metal posts attached to the merry-go-round with a horizontal force of 58.0 N to keep from sliding off. Jackie is sitting at the edge, a distance 3.67 m from the center.

With what horizontal force must Jackie hold on to keep from falling off?

If Jackie falls off, what will be her horizontal velocity when she becomes airborne?


I attempted this problem but got the wrong answer. What I did first was

58N = 29kg*V^2
=========
1.80

V = 1.89 m/s

Fnet = m*v^2
---------
R

Fnet = (29kg)(1.89m/s)^2
--------------------
3.67

Fnet = 28.4N


What did I do wrong?
 
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1.89 m/s is not the velocity of Jack. Their angular velocities is the same.
And angular velocity ω = v/R.
So v1/R1 = v2/R2. So find v2.
 
So

1.89m/s
-------- = V2/3.67m
1.80 m

V2 = 3.8585 m/s ?

Then

Fnet = (29kg)(3.8585m/s)^2/3.67m = 117.6N ?
 
Yes. That is right.
 

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