Mesh Currents with Differential Equations

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SUMMARY

This discussion focuses on the application of mesh currents in solving differential equations related to electrical circuits. The user expresses confusion regarding the relationship between mesh currents and physical currents, specifically questioning why the current i1 is not simply calculated as V/R. The conversation emphasizes the importance of understanding the behavior of capacitors at time t=0 and t=∞, suggesting that prior knowledge of capacitor charging and discharging is crucial for solving the problem without needing to solve differential equations.

PREREQUISITES
  • Understanding of mesh analysis in electrical circuits
  • Basic knowledge of differential equations
  • Familiarity with capacitor behavior during charging and discharging
  • Concept of Ohm's Law (V=IR)
NEXT STEPS
  • Review mesh analysis techniques in electrical engineering
  • Study the behavior of capacitors in transient circuits
  • Learn about the application of differential equations in circuit analysis
  • Explore examples of solving circuit problems at specific time intervals (t=0 and t=∞)
USEFUL FOR

Electrical engineering students, circuit designers, and anyone interested in understanding mesh analysis and capacitor behavior in transient conditions.

madbo517
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I've attached a picture of the problem statement, figure, and of my work so far.

I'm trying to use mesh currents and then differentiate it, but I really have no idea if I'm on the right track.

Also, I don't understand why i1 isn't just V/R (The physical current is the mesh current for R1, right?).

As you can tell, I'm pretty lost.
Would appreciate any help offered :)
 

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Because the problem only asks for what's happening at $t=0$ and $t=\infty$, you won't actually have to solve any DE's for this problem. Remember what a charged and discharged capacitor look like, right? So you can use that knowledge to determine the answers to the questions asked.
 

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