- #1

gcamilo

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## Homework Statement

I'm just not sure how to change the operators in summation, can anyone help?

Let [tex]s_{n}=\sum_{k=1} ^n ((-1)^{k+1})/k[/tex]

what is [tex]s_{2n}[/tex]?

## Homework Equations

[tex]s_{n}=\sum_{k=1} ^n ((-1)^{k+1})/k[/tex]

## The Attempt at a Solution

[tex]s_{2n}=\sum_{k=1} ^{2n} ((-1)^{2k+1})/2k[/tex]

or

[tex]s_{2n}=\sum_{k=1} ^{2n} ((-1)^{2k+2})/2k[/tex]

This is in order to figure out a series proof, I just think I am really naive.