hello everyone, i need some huge help here. heres the equation :(adsbygoogle = window.adsbygoogle || []).push({});

y''+y'-6y=10e^2x-18e^3x-6x-11.

complementary solution:c1e^2x+c2e^-3x

s1={e^2x}

s2={e^3x}

s3=(x,1}

ok since e^2x exists in the complimentary solution, it is therefore a solution, so i multiply it by x to get s'1{xe^2x}, so now i have that and my s2 and s3.

so i end up with this:

yp=Axe^2x+Be^3x+Cx+D

heres where i get confused do i use the product rule for Axe^2x, if so do i end up with these two derivatives: y'p=Axe^2x+2Ae^2x+...etc, y''p=Axe^2x+4Ae^2x+...etc. i really get confused with this product rule thing.

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Method of undetermined coefficients

Loading...

Similar Threads - Method undetermined coefficients | Date |
---|---|

Is It Possible to Use the Method of Undetermined Coefficients Here? | Jul 13, 2014 |

Method of Undetermined Coefficients for Higher Order Linear Equations | May 5, 2013 |

Method of undetermined coefficients, when to raise the guess | Jun 3, 2012 |

Method of Undetermined Coefficients | Jun 4, 2011 |

How to use of the method of undetermined coefficients | Dec 27, 2010 |

**Physics Forums - The Fusion of Science and Community**