Method of Variation of parameters

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To solve the differential equation y'' + y' = 2^x using the method of variation of parameters, the auxiliary equation is r^2 - r = 0, yielding roots r = 0 and r = 1. The complementary function, yc, can be found using these roots, typically as a linear combination of e^(0x) and e^(1x), resulting in yc = C1 + C2e^x. It's important to note that the method of variation of parameters focuses on finding a particular solution, yp(x), rather than the complementary function itself. Clarification on terminology is essential, as the complementary function is distinct from the method being discussed. Understanding these concepts is crucial for effectively applying the method of variation of parameters.
s7b
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Hi,

When using the method of variation of parameters to solve something like;

y'' + y' = 2^x

I got the aux. equation: r^2 - r =0 which gives the roots r=0,1

How do I find the complementary equation yc?
 
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what is the aux. eqn? did you solve the homogenous eqn by assuming an exponential then differentiating and plugging in?
 
s7b said:
Hi,

When using the method of variation of parameters to solve something like;

y'' + y' = 2^x

I got the aux. equation: r^2 - r =0 which gives the roots r=0,1

How do I find the complementary equation yc?

If you meant complementary function then it got nothing to do with the method of variation of parameters. The method is meant for computing a particular solution yp(x).
 

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