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Visual1Up

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A car going 15m/s is brought to rest in a distance of 2.0m as it strikes a mound of dirt. How large an average force is exerted by the seatbelts on a 90kg passenger as the car is stopped.

I have found one formula... F = (mass * change in velocity)/time ... and I have found stopping time to be approx (2.0/15) = 1.33 (unless I am wrong) so F = (90 (not sure about this) * 15)/1.33 = 10125N

The only problem is I have the right answer from a friend that is approx 5100N. Can someone tell me what's going wrong? Thanks!,

-Mike